Frequent Visitor
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7 Messages
Additional external IP address
Hello,
I would like to add an additional external IP address to my CM1000 modem, but appears this feature was eliminated for resedential service. I see that some exceptions can be made so I am hoping you can assist in allowing me to add this additional address. Any assistance would be appreciated. Thanks in advance.
Responses
EG
Expert
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87K Messages
10 m ago
They are phasing it out but I'm going to escalate your issue to the Comcast corporate employees that are available to these boards. We've seen cases here where they have been able to get this accomplished for customers even when it is not listed in their rate cards, YMMV. You should get a reply here in your topic. Good luck !
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terminalv
Frequent Visitor
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7 Messages
10 m ago
Thanks so much. I appreciate the quick response and the assistance.
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EG
Expert
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87K Messages
10 m ago
Quite welcome !
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ComcastJoeTru
Official Employee
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6.7K Messages
10 m ago
Hello terminalv. Thank you for visiting and posting on our Forum. I can assist with reviewing your account to see if you are in an area where we have a 2nd additional IP address available for lease. If you would like assistance, please send me a private message and include your full name and service address so I can access your account. To send a private message: click my name (ComcastJoeTru) to view my profile. Then click the link that says "Send a message" and there you can private message me.
Official Employees are from multiple teams within Comcast: CARE, Product, Leadership. We ask that you post publicly so people with similar questions may benefit from the conversation.
Was your question answered? Please, mark a reply as the Accepted Solution.
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terminalv
Frequent Visitor
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7 Messages
9 m ago
Hi Joe,
I am not able to see the 2nd dynamic IP. It is listed on the account but I am not able to get a second address through my CM1200 modem. Can you please help me get this going. I have spent a couple hours with support and they do not have the resources to assist with this problem. Thanks,
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